Each of the following sets of quantum numbers is supposed to specify an orbital Choose the one set of quantum numbers that does NOT contain an error. a) n=4, I=4, m/=1
b) n=5, I=3, m/=- 3
c) n=3, I=1, m/= -2
d) n=3, I= 2, m/=+3 ​

C

Explanation:

The correct answer is C because the first quantum numbers containing and encompass in an orbital m contain a definite she'll of 2 and hence

the answer is b. dilution

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2