2 H2O2 2H2O + O2 V O2 = 63 mL, P=1.008 atm, T=294 K, R=0.0831
amount of 2H2O2 in experiment was 5mL
1. using ideal gas law, n = PV/RT find moles of O2.
2. Find theoretical moles of O2
3. Using actual moles and theoretical moles calculate the percentage hydrogen peroxide in your experiment.

1 is the answer to this problem

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.