Se colocan 0,400 moles de O2 ( g ) y 30,0 g de CO2 ( g ) en un recipiente rígido. La presión es de 0,352 atm y la temperatura 5,00 ºC. Calcular el volumen del recipiente. Datos: R = 0,082 dm3 . atm . mol-1 . K-1 ; Mr ( CO2 ) = 44,0

The answer is probably c. xylem

The correct answer to this question is 28 

Using dilution equationm1v1 =m2v2 ; where m1 and m1 are the intiial and final concentration, and v1 and v2 are the initial and final volume.5  × 5 m = 8 l  × m2m2 = 25/8 = 3.125 mtherefore; the resulting molarity is 3.125 m

Answer is: hydrogen is being oxidized.chemical reaction: co₂ + h₂ → co + h₂o.oxidation half reaction: h₂ → 2h⁺ + 2e⁻.reduction half reaction: c⁺⁴ + 2e⁻ → c⁺².oxidation is increase of oxidation number, hydrogen change oxidation number from neutral charge (in molecule of hydrogen) to oxidation number +1 (in water).