Chemistry, 06.05.2021 08:50 Annabel9554
How would you draw a galvanic cell for Aluminum and Charcoal?
Anode: Al(s) + 3OH-(aq) >>>> Al(OH)3(s) + 3e-
E cell/V: -2.31
Cathode: O2(g) + 2H2O(l) +4e- >>>> 4OH-(aq)
E cell/V: 0.401
Overall: 4Al(s) + 3O2(g) + 6H2O(l) >>>> 4Al(OH)3(s)
Answers: 2
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How would you draw a galvanic cell for Aluminum and Charcoal?
Anode: Al(s) + 3OH-(aq) >>>...
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