For the reaction: N2(g) + O2(g) 2NO(g), the Keq at 2130°C is 0.0025. If [N2] = 0.75 M, [O2] = 0.30 M, and [NO] = 0.090 M, calculate Q and in which direction will the reaction shift? A.
3.6 × 10-2; shift to right
B.
3.6 × 10-2; shift to left
C.
4.0 × 10-1; shift to right
D.
4.0 × 10-1; shift to left

n+h→nh3

we must remember that nitrogen and hydrogen are both diatomic molecules in their standard gas form. this adjusts the equation to

n2+h2→nh3

now we need to adjust coefficients in order to balance the atoms on each side of the equation. currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.

we can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.

n2+3h2→2nh3

this gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.

the answer is 75.0%.