How much energy is required to heat 2kg of water through the following changes?

Total heat = Heat required to convert 2kg of ice to 2kg of water at 0℃ +Heat required to convert 2kg of water at 0℃ to 2kg of water at 20℃

Heat=mhfg+mCp\Delta t$$

Here, m(mass of ice)=2kg

hfg(latent heat of fusion of ice)=334kJ

Cp of water(specific heat)=4.187 kJ/kg-k

Δt(temperature difference) =20℃

Therefore,

Heat required=2×334+2×4.187×(20−0)

nacl is added to the aqueous of what? ? in order to get a proper answer you have to specify the exact composition of the aqueous solution.

what are the statements