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Chemistry, 05.05.2021 06:20 anyaivy44

Study the reaction. 2HCl (g)+l_2 (s)β‡Œ2Hl (g)+Cl_2 (g)
When the reaction is at equilibrium, some amount of HI is added. The system then reaches equilibrium again.

How does the concentration of Cl2 change compared to the first equilibrium?

The concentration is the same.

The concentration is higher.

The concentration is lower.

The concentration is zero.

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Study the reaction. 2HCl (g)+l_2 (s)β‡Œ2Hl (g)+Cl_2 (g)
When the reaction is at equilibrium, s...
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