Free Response Question - PLEASE HEL 5880 grams of paraffin wax, C25H52 are burned in excess oxygen at 520 C in a rigid 150 Liter container according to the following equation:
C25H52 + O2(g) --> CO2(g) + H2O(g)

a) Balance the equation
b) Calculate the pressure of carbon dioxide gas when the reaction goes to completion
c) Calculate the pressure of water vapor when the reaction goes to completion
d) If there are 18.55 moles of oxygen gas leftover in the container along with the carbon dioxide and water vapor when the reaction goes to completion, what is the total pressure of the system?
e) The rigid container is opened, explain which gas is going to effuse faster, water vapor or oxygen gas? Prove mathematically how much faster.

PLEASE SHOW WORK

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6