The formation of tin IV chloride is as follows; the change in enthalpy is (AH) is -511 kJ/mole. Sn (s) + 2 C12 (9) --> SnC14 (1) + Heat
The reaction would be considered?
A. Endothermic, releases heat
B. Exothermic, release heat
C. Endothermic, absorbs heat
D. Exothemric, absorbs heat

answer; blank (1); /// (2)///(3)///highblank(4)//low;

i dont know

explanation:

d.) circle motion requires a force to give it a centripetal acceleration.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"