2) Determine the value of the enthalpy change, AH vap, for the evaporation of one mole of water using the information below. H2O(l) → H2O(g)
CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(l) AH= -890.5 kJ/mol
CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(g) AH= -802.3 kJ/mol

it’s previous models   because when i picked that son of a gun’s answer it was wrong look for previous models because they might make it a different letter  

there are two significant figures.

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.