Chemistry, 01.05.2021 14:30 lizdeleon248
471 mL of 2.013 M linthium baltimide (LiBr, 84.781 g/mol) is combined with 380 mL of 6.582 M shorium baltimide (SrBr2, 245.056 g/mol) to make a homogeneous mixture. What is the concentration of baltimide ions (Br-) in the new solution?
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471 mL of 2.013 M linthium baltimide (LiBr, 84.781 g/mol) is combined with 380 mL of 6.582 M shorium...
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