using the ideal gas law formula PV = nRT, where R=62.4 mm L/K mol, solve for moles when the V= 3.2 L, P = 740 mm and T=- 35° c (remember to convert to k = 73 +°c) A. 6.3 moles B. 8.1 moles C. 0.16 moles D. 0.12 moles​

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when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

5.6⋅10−^19  j

do you need the explaination?