Question: In the Reaction: CuCl2 + 2 NaNO3 -- Cu(NO3)2 + 2 Naci
If 17.2 grams of copper (II) chloride, CuCl2, reacts with 22.6 grams of sodium nitrate, NaNO3. how many grams of sodium chloride, NaCl, will be
produced? (4 points)
Molar mass of CuCl2 = 134.45 g/mol
Molar mass of NaNO3 = 85.00 g/mol
Molar mass of NaCl = 58.44 g/mol
Answers:
17.2 grams CuCl2 =
gNaci
v
22.6 grams NaNO3 =
g Naci
What is the Limiting Reactant?
No

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