Cu+2 + 2e -> Cu E = 0.52 V Ag+1 + 1e -> Ag E° = 0.80 V
Using the two cell reduction potentials shown for their corresponding reaction,
calculate the cell potential for a voltaic cell made from these two metals.
A) 1.32 V
B) -1.32 V
C) -0.28 V
D) 0.28 V