What is the equilibrium constant for the chemical equation: Mg3P2 (s) ++ 3Mg+2 (aq) + 2P-3
(aq)
At equilibrium, the concentration of Mg3P2 is 5.5 x 10-6 M, the concentration of magnesium ions is 7.2 x 10
5 M, and the concentration of phosphide ions is 9.8 x 10-8 M.
Write out the equilibrium constant, Keg. and show you work.

Cause its being chemically applied?

Hi hi answer is and

2poclâ‚(g) ⇜ 2 pclâ‚(g) + oâ‚‚(g) â†gâ° = (2 mol)î”gfâ°(pclâ‚) – (2 mol)î”gfâ°(poclâ‚) = (2 mol)(–270 –(–502) kj/mol) â†gâ° = + 464 kj = â†hⰠ– tî”sâ° î”sâ° = 179 j/k ⇒ â†hâ° = â†gâ° + (298 k)(179 j/k) = –411 kj assuming that î”hâ° and î”sâ° do not depend on temperature, the temperature at which â†gâ° = 0 is where t = â†hâ°/î”sâ° = (–411 kj)/(0.179 j/k) = 2294 k. at that temp. keq = 1 for the reaction.