Calculate delta G for the following rxn at 25 degrees celcius. 3Mn2+ (aq) + 2Al(s) -><- 3Mn(s) + 2Al3+ (aq)

The
anode= Mn2+ + 2e- -> Mn
= -1.18 V
The
Cathode= Al3+ + 3e- -> Al
= -1.66 V

The Ecell= -1.66-(-1.18)= -0.48 V

But I do not know how to find Delta G.
Delta G= -nFE

The answer is in kj/mol.
Can anyone help?

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

the correct answer would be b) volume versus temperature, because they are also directly proportional.