Chemistry, 23.04.2021 21:00 ptanner706

The equation for the combustion of methanol is 2CH3OH + 302 =2CO2 + 4H2O. How many liters of carbon dioxide are produced by the combustion of 64.0 g of methanol (CH3OH)? 22.4 L CO.
89.6 L CO2
11.2 L CO2
44.8 L CO.

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The equation for the combustion of methanol is 2CH3OH + 302 =2CO2 + 4H2O. How many liters of carbon...

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The equation for the combustion of methanol is 2CH3OH + 302 =2CO2 + 4H2O. How many liters of carbon dioxide are produced by the combustion of 64.0 g of methanol (CH3OH)? 22.4 L CO. 89.6 L CO2 11.2 L CO2 44.8 L CO.​

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The equation for the combustion of methanol is 2CH3OH + 302 =2CO2 + 4H2O. How many liters of carbon dioxide are produced by the combustion of 64.0 g of methanol (CH3OH)? 22.4 L CO.
89.6 L CO2
11.2 L CO2
44.8 L CO.