Chemistry, 20.04.2021 22:50 rivermadds3117

Heredity Lab Report Instructions: In the Heredity lab, you investigated how hamsters inherit traits from their parents.
Record your observations in the lab report below. You will submit your completed report.
Name and Title:
Include your name, instructor's name, date, and name of lab.
Objective(s):
In your own words, what was the purpose of this lab?
Hypothesis:
In this section, please include the if/then statements you developed during your lab activity.
These statements reflect your predicted outcomes for the experiment.
Test One: If I breed a short fur, FF female with a short fur, Ff male, then I will expect to see (all
short fur; some short and some long fur; all long fur) offspring.
Test Two: If I breed a short fur, Ff female with a short fur, Ff male, then I will expect to see (all
short fur; some short and some long fur; all long fur) offspring.
Test Three: If I breed a long fur, ff female with a long fur, ff male, then I will expect to see (all
short fur; some short and some long fur; all long fur) offspring.
Procedure:
The procedures are listed in your virtual lab. You do not need to repeat them here. Please be sure
to identify the test variable (independent variable) and the outcome variable (dependent variable)
for this investigation.
Remember, the test variable is what is changing in this investigation. The outcome variable is
what you are measuring in this investigation.
Test variable (independent variable):
Outcome variable (dependent variable):
Data:
Record the data from each trial in the data chart below. Be sure to fill in the chart
completely.
Test One
Parent 1: FF
Parent 2: Ff
Phenotype ratio:
Test Two
Parent 1: Ff
Parent 2: Ff
:
short fur : long fur
Phenotype ratio:
Test Three
Parent 1: ff
Parent 2: ff
:
short fur : long fur
Phenotype ratio:
Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results.
Please write in complete sentences.
1. Which genotype(s) and phenotype for fur length are dominant?
2. Which genotype(s) and phenotype for fur length are recessive?
:
short fur : long fur
3. If you have a hamster with short fur, what possible genotypes could the hamster have?
4. If you have a hamster with long fur, what possible genotypes could the hamster have?
5. Did your data support your hypotheses? Use evidence to support your answer for each
test.
o Test One:
o Test Two:
o Test Three:
6. Which hamsters are the parents of the mystery hamster? Include evidence to prove that
they are the correct parents.

Answers: 3

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Answers

Answer from: Quest

Wish i can but don’t know this

Answer from: Quest

each chemical family is represented as a group or column on the periodic table. based on chemical properties, there are 6 types of chemical families. group 1 represents alkali metals, group 2 represents alkaline earth metals, groups 3 to 12 represent transition metals, groups 13 to 16 represent non-metals and other metals, group 17 represents halogens and group 18 represents noble gases.

Answer from: Quest

remember that hf is only the energy of one photon. not two. not three. one. 1) 5.12 * 10^3 photons find the energy of one photon, then determine how many photons are needed to reach the sensitivity. e = hf = (6.626 * 10^-34 js)(5.95 * 10^19 hz) = 3.94247 * 10^-14 j per photon (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons round to three sig figs. 2) 5.77 * 10^-17 j energy of pulse = energy per photon * number of photons = hfn = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250) = 5.774559 * 10^-17 j round to three sig figs. 3) 4.07 * 10^8 kj/mol 10^12 pm = 1 m c = fλ f = c/λ e = hf = hc/λ = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol) = 40702571.4 kj/mol round to three sig figs. 4) 9.94 * 10^-1 m e = hc/λ λ = hc / e = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j) = 0.9939 m round to three sig figs. 5) 9.06 * 10^3 photons energy of pulse = energy per photon * number of photons number of photons = energy of pulse / energy per photon = energy of pulse / (hf) = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)] = 9055.23695 photons round to three sig figs. 6) 2.78 * 10^-15 j this is problem 1, except in reverse. sensitivity = minumum number of photons * energy per photon = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz) = 2.78070758 × 10^-15 j round to three sig figs.

Answer from: Quest

if the temperature drops and becomes cool

then the atmosphere can be freezing as the water vapor in the air is at maximum (100%) and can be severely cold

also can be snowing lightly as the moisture in the air will start to solidify

and btw this is not chemistry but

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Heredity Lab Report Instructions: In the Heredity lab, you investigated how hamsters inherit trait...

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