When copper sulphate is dissolved in water in a beaker, a bright blue liquid or solution is formed. If copper sulphate is added until no more will dissolve, a saturated solution is formed. Some blue crystals will remain at the bottom of the beaker. What was the solvent used?
What was the solute used?
What has happened to the copper sulphate?
What would you call the bright blue liquid?
What would you call the liquid at the end of the experiment?
What type of solution was formed?
You would like to separate the crystals. Name the method of separation that would be best to use? Hi

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

a polar bond is formed when electrons are shared unevenly between atoms

it is the most commonly accepted one