Chemistry, 31.08.2019 03:50 rdrboo

What is the symbol for the isotope of 58 co that possesses 33 neutrons?

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Answer from: yoongnzl

Element with an atomic number of 58 is actually Cerium, so the symbol should be Ce, not Co because that is Cobalt which has an atomic number of 27. With that being said, the notation for isotopes is the symbol of the element with a superscript and a subscript that are aligned. The superscript represents the mass number.

Mass number = protons + neutrons = 58 + 33 = 91

The subscript is the atomic number which is 58. The notation is written in the picture attached.
What is the symbol for the isotope of 58 co that possesses 33 neutrons?

What is the symbol for the isotope of 58 co that possesses 33 neutrons?

Answer from: lovely222

The symbol for the isotope :

$\large {{{91} \atop {58}} \right Ce}$

Further explanation

The elements in nature have several types of isotopes

Isotopes are atoms whose no-atom has the same number of protons while still having a different number of neutrons.

So Isotopes are elements that have the same Atomic Number (Proton)

Atomic mass is the average atomic mass of all its isotopes

In determining the mass of an atom, as a standard is the mass of 1 carbon-12 atom whose mass is 12 amu

So the atomic mass obtained is the mass of the atom relative to the 12th carbon atom

$\large {\boxed {mass ~ average ~ atom ~ X ~ = ~ \frac {mass\:isotope ~ 1 + mass ~ isotope ~ 2} {number ~ whole ~ atom ~ X}}$

An atomic mass unit = amu is a relative atomic mass of 1/12 the mass of an atom of carbon-12.

$\large {\boxed {Ar ~ X = \frac {mass ~ average ~ 1 ~ atom ~ X} {\frac {1} {12}. mass ~ 1 ~ atom ~ C-12}}}$

The 'amu' unit has now been replaced with a unit of 'u' only

for example, Carbon has 3 isotopes, namely ₆¹²C12, ₆¹³C, and ₆¹⁴C

The Atomic Number (Z) indicates the number of protons in an atom of an element. If the atom is neutral then the number of protons will be equal to the number of electrons. So the atomic number can also indicate the number of electrons.

So atomic number = number of protons = number of electrons

Mass Number (A) is the sum of protons and neutrons

Mass Number (A) = Number of protons + Number of Neutrons

So that the relationship between atomic numbers and mass numbers can be formulated as follows:

Atomic Number (Z) = Mass Number (A) - Number of Neutrons

In the following element notation,

$\large {{{A} \atop {Z}} \right X}$

Information

X = symbol of elemental atom

A = mass number

= number of protons + number of neutrons

Z = atomic number

= number of protons = number of electrons, on neutral elements

The symbol for the isotope of 58 that possesses 33 neutrons

The number of 58 indicate the Atomic Number (Z) = number of protons

And the mass number :

A = number of protons + number of neutrons

A = 58 + 33

A = 91

Whereas the element that has atomic number 58 is must be Serium (Ce)

So the symbol for the isotope :

$\large{\boxed{\bold{ {{{91} \atop {58}} \right Ce}}}}$

Learn more

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the chemical symbols

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two stable isotopes of bromine

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Keywords : the symbol,the isotope, Ce, atomic number , mass number

Answer from: Quest

Usually this mountain-building process produces majestic peaks and steep slopes. you should look for these along the other features.

Answer from: Quest

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 : $4x (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) h rxn = -600 kj/mol$

equation 2 : $2x (s) + 3cl_{2} (g) \rightarrow 2xcl_{3} (s) h rxn = -800 kj/mol$

equation 3 : $4xcl_{3} (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) + 6cl_(2} h rxn = -200 kj/mol$

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 : $4xcl_{3} (s) \rightarrow 4x (s) + 6cl_{2} ( h rxn = (+800) \times 2 kj/mol$

let us add equation 1 & 4

$4x (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) h rxn = -600 kj/mol$

$4xcl_{3} (s) \rightarrow 4x (s) + 6cl_{2} ( h rxn = (+1600) kj/mol$

$4xcl_{3} )s) + 3o_{2} \rightarrow 2x_{2}o_{3} (s) + 6cl_{2} (g) h rxn = (+1000) kj/mol$

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

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