The balanced equation below represents the reaction of glucose, c6h12o6, with oxygen at 298 k and 101.3 kpa.
c6h12o6(s) + 6o2(g) → 6co2(g) + 6h2o(ℓ)
determine the mass of co2 produced when 9.0 grams of glucose completely reacts with 9.6 grams of oxygen to produce 5.4 grams of water. [1]
compare the entropy of the reactants to the entropy of the products. [1]
write the empirical formula for glucose. [1]

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%