How much heat is needed to raise the temperature of 5.58 kilograms of iron from 20.0 celsius to 1000.0 celsius? specific heat of iron is 450,000 j/(kgx celsius).
type the correct answer to 3 significant digits. if the answer has an exponent, type the number, then ^, then the exponent.

Mass = m = 5.58 kg
specific heat index = c = 450000 J/(kg*C)
deltaT = change in temperature = 1000-20 = 980

Plug those three values into the formula below
Q = mc*(delta T)
Q = 5.58*450000*980
Q = 2,460,780,000

Rounding to three sig-figs, we will get the final answer to be 2,460,000,000
Note: this number is 2.46 billion (equivalent to 2 billion, 460 million)

Idon't know hope someone you

Use a magnet to separate iron, evaporate water, i'm not sure how to separate the other two i'm sorry but good luck