A20.0-milliliter sample of hcl(aq) is completely neutralized by 32.0 milliliters of 0.50 m koh(aq).
calculate the molarity of the hcl(aq). your response must include both a numerical setup and the calculated result.

You can use the formula M1 x V1 = M2 x V2 where M1 is the molarity of the first substance and V1 is the volume of the substance. M2 is the molarity of the 2nd substance and V2 is the volume of the substance

if substance 1 is HCl and 2 is KOH we can set up the following equation

x moles / liter (unknown) x .02 liters = .5 moles/ liter x .032 liters

x moles / liter x .02 liters = .016 moles

x moles / liter = .016/.02 liters

x moles / liter = .8 moles/ liter
 
You have . 8M HCL 

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