Given the balanced equation representing a redox reaction:
2al + 3cu2+ --> 2al3+ + 3cu
which statement is true about this reaction?
(1) each al loses 2e- and each cu2+ gains 3e-
(2) each al loses 3e- and each cu2+ gains 2e-
(3) each al3+ gains 2e- and each cu loses 3e-
(4) each al3+ gains 3e- and each cu loses 2e-

From the given balanced chemical reaction, it can be seen that each aluminum atom gains loses 3 electrons. Also, each copper atoms gains 2 electrons. The choice that would best give us the described scenario above is choice number 2. That is Each Al loses 3e- and each Cu gains 2e-.

The correct answer is option (2) i.e. Each Al loses 3e- and each Cu^2+ gains 2e- When an atom X, loses an electron, it becomes, X^1+ When an atom X, loses two electrons, it becomes, X^2+ When an atom X, gains an electron, it becomes, X^1- When an atom X, gains two electrons, it becomes, X^2- So, Here, 2Al + 3Cu^2+ --> 2Al^3+ + 3Cu, When each Al, loses three electrons, it becomes, Al^3+ When each Cu^2+, gains two electrons, it becomes, Cu^2+^2- = Cu