Scientists who do carbon 14 dating use 5700 years for its half life. find the age of a sample in which 10% of the radioactive nuclei originally present have decayed

For this problem, we use the formula for radioactive decay which is expressed as follows:

An = Ao (e^-kt)

where An is the amount left after time t, Ao is the initial amount and k is a constant determined experimentally. 
First, we calculate for the value of k from the data we have of the half life. We do as follows:

An = Ao (e^-kt)
0.5 = e^-k(5700)
k = 1.21x10^-4 / year

After solving for k, we can use this value to solve for the age of the sample given the percent of the carbon nuclei that is remained after that particular time,

An = Ao (e^-kt)

An/Ao = e^-kt
1 - .10 = e^-1.21x10^-4(t)
t = 878.00 years

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.  

the old alchemists made significant contributions to science even though there starting premises were off a bit. their conclusions after failure would steer them into better directions for investigation. science is no more than close observation and the initial mistakes result in rethinking and retrying experiments.