Acar initially at rest undergoes uniform acceleration for 6.32 seconds and covers a distance of 120 meters. what is the approximate acceleration of the car?
a.) 5 meters/second2
b.) 6 meters/second2
c.) 9 meters/second2
d.)12 meters/second2
e.)37 meters/second2

Use the equation for uniform acceleration:

distance = Vo*t + a * t^2 / 2

As the car is initially at rest, Vo = 0

=> distance = a * t^2 / 2.

Now solve for a and replace the data of time and distance:

a = 2 * distance / (t^2)

a = 2 * 120m / (6.32s)^2 = 240m / 39.9424 s^2 = 6.009 m/s^2

Which approximates to 6 m/s^2.

So, the answer is the option B.) 6 meters / second^2

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