Chemistry, 05.02.2020 06:43 odellbeckham43881

Utilizing dimensional analysis, find the number of inches in a kilometer given that 1 inch = 2.54 centimeters

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Answer from: geraldsmith2008

To answer this item, we need to utilize the appropriate the conversion factors and the dimensional analysis.

Our basis for solving is 1 kilometers. It is known that each kilometer is composed of 1000 meters.

(1 km) x (1000 m/1 km) = 1000 m

Next, we need to determine the number of centimeters. The conversion factor that can be used is 1 meter = 100 centimeters
(1000 m) x (100 cm/ 1 m) = 100,000 cm

Lastly, we use the given conversion factor to convert the centimeters to inches.

(100,000 cm) x (1 inch / 2.54 cm)
= 39,370.08 in

ANSWER: Each kilometer is composed of 39,370.08 inches

Answer from: Quest

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

Answer from: Quest

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 : $4x (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) h rxn = -600 kj/mol$

equation 2 : $2x (s) + 3cl_{2} (g) \rightarrow 2xcl_{3} (s) h rxn = -800 kj/mol$

equation 3 : $4xcl_{3} (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) + 6cl_(2} h rxn = -200 kj/mol$

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 : $4xcl_{3} (s) \rightarrow 4x (s) + 6cl_{2} ( h rxn = (+800) \times 2 kj/mol$

let us add equation 1 & 4

$4x (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) h rxn = -600 kj/mol$

$4xcl_{3} (s) \rightarrow 4x (s) + 6cl_{2} ( h rxn = (+1600) kj/mol$

$4xcl_{3} )s) + 3o_{2} \rightarrow 2x_{2}o_{3} (s) + 6cl_{2} (g) h rxn = (+1000) kj/mol$

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

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Utilizing dimensional analysis, find the number of inches in a kilometer given that 1 inch = 2.54 ce...

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