A25.00 ml sample of naoh is titrated with a 0.1000m h2so4 solution. what is the concentration of the naoh if it takes 18.45 ml of the h2so4 solution to reach the equivalence point of the titration?

The chemical reaction involved in this titration process would be:

2NaOH + H2SO4 = Na2SO4 + 2H2O

To determine the concentration of the NaOH solution, we need to first calculate for  the moles of NaOH that is used up in the reaction given the amount of H2SO4 solution that is used. We do as follows:

Moles NaOH = 0.100 M H2SO4 ( .01845 L solution ) ( 2 mol NaOH / 1 mol H2SO4 ) = 3.69x10^-3 mol NaOH reacted

Volume of NaOH = .025 L

Molarity is the number of moles of a solute per liter of solution. We calculate as follows:

Molarity of NaOH = 3.69x10^-3 mol NaOH / .025 L = 0.1476 M

the answer would be a

the answer is c. nacl