Asolution contains 2 meq/ml of kcl. if a 20 ml ampule of this solution is diluted to 1 liter what is the percent strength of the resulting solution

We are given that the concentration of the KCl is 2 meq / mL. Assuming that the ampule also has exactly this concentration, therefore:

amount of KCl in ampule = (2 meq / mL) * (20 mL)

amount of KCl in ampule = 40 meq

This amount of KCl is now inside a solution of 1 Liter (also equivalent to 1000 mL), therefore the new concentration in the resulting solution is:

new concentration = 40 meq / 1000 mL

new concentration = 0.04 meq / mL

Since 0.04 in decimal is 4% in percentage, therefore the strength of the resulting solution is 4% KCl.

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.