Calculate the amount of heat required to vaporize 84.8 g of water at its boiling point.

You need to use the specifc latent heat of vaporization of water which you can find in internet.

I found 2,264.76 KJ / kg = 2,264.76 J/g

Now use total heat = specific latent heat * mass

=> 84.8 g * 2,264.76 J/ g = 192,051.65 J.

192,051.65 J

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