Calcium carbonate (caco3), an important component of coral reefs, can decompose when heated, forming calcium oxide (cao) and carbon dioxide (co2) according to the equation below: caco3 es002-1.jpg cao + co2 how many moles of cao form when 98.60 g caco3 decompose?

1) Chemical equation

CaCO3 ---> CaO + CO2

2) Molar ratios

1 mol CaCO3 : 1 mol CaO : 1 mol CO2

3) Number of moles of reactant: 98.60 g CaCO3

3.1) Calculate the molecular mass of CaCO3:

40.08 g/mol + 12.00 g/mol + 3*16.00 g/mol = 100.08 g / mol

3.2) Calculate thte number of moles using the formula numbe of moles = mass in grams / molecular mass

=> number of moles = 98.60 g / 100.08 g / mol = 1.015 mol of CaCO3

4) Using the theoretical molar ratios you know 1 mole of CaCO3 produce 1 mol of each product, then with 1.015 mol of CaCO3 you will obtain 1.015 mol of CO, which rounded to 3 significant figures is 1.02 mol.

1.02 mol

m=9

step-by-step explanation:

7m+8=71 subtract   8 from 71 which is 63 than divide it by 7m   equal 9.