The molar heat capacity for carbon monoxide at constant volume is cv, m = 20.17 j/(k·mol). a 18.00-l fixed-volume flask contains co(g) at a pressure of 2.00 kpa and a temperature of 25.0 °c. assuming that carbon monoxide acts as an ideal gas and that its heat capacity is constant over the given temperature range, calculate the change in entropy for the gas when it is heated to 800.0 °c.
Answers: 1
Chemistry, 22.06.2019 05:40
Calculate: select the worksheet tab. this tab you calculate the analyte concentration. fill in the first set of boxes ("moles h2so4" and "moles naoh") based on the coefficients in the balanced equation. (if there is no coefficient, the value is 1.) record the appropriate volumes in the "ml naoh" and "ml h2so4" boxes. record the concentration of the titrant in the m naoh box. click calculate. what is the concentration listed
Answers: 2
Chemistry, 22.06.2019 07:00
Achemist wants to extract copper metal from copper chloride solution. the chemist places 0.50 grams of aluminum foil in a solution containing 0.75 grams of copper (ii) chloride. a single replacement reaction takes place. (ii) chloride. a single replacement reaction takes place. which statement explains the maximum amount of copper that the chemist can extract using this reaction? a) approximately 0.36 grams, because copper (ii) chloride acts as a limiting reactant b) approximately 1.8 grams, because copper (ii) chloride acts as a limiting reactant c) approximately 0.36 grams, because aluminum acts as a limiting reactant d) approximately 1.8 grams, because aluminum acts as a limiting reactant
Answers: 3
Chemistry, 22.06.2019 15:20
Select the most likely product for this reaction: koh(aq) + co2(g) – ? k2co3(aq) + h2o(1) k(s) + h2(g) + o2(g) k(s) + co3(9) +h2
Answers: 2
The molar heat capacity for carbon monoxide at constant volume is cv, m = 20.17 j/(k·mol). a 18.00-l...
Law, 21.09.2021 21:50
Mathematics, 21.09.2021 21:50
Mathematics, 21.09.2021 21:50
Mathematics, 21.09.2021 21:50
Chemistry, 21.09.2021 21:50
Engineering, 21.09.2021 21:50