Magnesium burns in air with a dazzling brilliance to produce magnesium oxide: 2mg(s) + o2(g) ? 2mgo(s) when 4.00 g of magnesium burns, the theoretical yield of magnesium oxide is

The theoretical yield of magnesium oxide is 6.65 grams.

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of magnesium = 4.00 g

Molar mass of magnesium = 24.3 g/mol

Putting values in equation 1, we get:

The given chemical equation follows:

By Stoichiometry of the reaction:

2 moles of magnesium produces 2 moles of magnesium oxide

So, 0.165 moles of magnesium will produce = of magnesium oxide

Now, calculating the theoretical yield of magnesium oxide by using equation 1:

Molar mass of magnesium oxide = 40.3 g/mol

Moles of magnesium oxide = 0.165 moles

Putting values in equation 1, we get:

Hence, the theoretical yield of magnesium oxide is 6.65 grams.

output?

explanation: