What is the predicted change in the boiling point of water when 4.00 g of barium chloride is dissolved in 2.00 kg of water?

BaCl2 has molar mass of 208.23 g/mol

Boiling point of elevation can be calculated using the formula:

ΔTb = iKbm

Where:

i = van’t Hoff factor  (This is 3 for BaCl2 since it dissociates to 3 ions)

Kb = molal boiling point constant for water (0.51 °C/m)

m = molality of solution

Substituting the values into the equation:

ΔTb = 3*0.51*(4/(2*208.23))

ΔTb = 0.0147°C or 0.015°C

the answers are

c and c