Asolution of water (kb=0.512 ? c/m) and glucose boils at 103.06 ? c. what is the molal concentration of glucose in this solution? assume that the boiling point of pure water is 100.00 ? c.

When a solute is added to a solvent, some properties are affected and these set of properties are called colligative properties. The properties depend on the amount of solute dissolved in a solvent. For this we use the boiling point elevation of the solution. We do as follows:

ΔT(boiling point) = 103.06 °C - 100.0 °C= 3.06 °C
ΔT(boiling point)  = (Kb)m
m = ΔT(boiling point) / Kb
m =  3.06 °C / 0.512 °C kg / mol
m = 5.98 mol / kg

D. is the answer hope that you

The answer is probably c. xylem