If the ph of a 1m naoh solution is 11.3 what is the h+ concentration for that solution?

[H+] = ?

pH = -log[H+]
[H+] = 10^-pH

[H+] = 10^-11,3
[H+] = 5,01 × 10^-12 mol/l

H+ concentration in this solution equal 5,01 × 10^-12 mol/l.

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