The equation below shows lithium reacting with nitrogen to produce lithium nitride. 6li + n2 mc007-1.jpg 2li3n if 12 mol of lithium were reacted with excess nitrogen gas, how many moles of lithium nitride would be produced?
4.0 mol
6.0 mol
12 mol
36 mol

Answer is: 4.0 mol of lithium nitride would be produced.

Balanced chemical reaction: 6Li + N₂ → 2Li₃N.

n(Li) = 12 mol; amount of substance.

From chemical reaction: n(Li) : n(Li₃N) = 6 : 2 (3 : 1).

n(Li₃N) = n(Li) ÷ 3.

n(Li₃N) = 12 mol ÷ 3.

n(Li₃N) = 4 mol; amount of lithium nitride.

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