Astudent requires 2.00 l of 0.100 m nh4no3 from a 1.75 m nh4no3 stock solution. what is the correct way to get the solution?
use mc021-1.jpg.

measure 114 ml of the 1.75 m solution, and dilute it to 1.00 l.

measure 114 ml of the 1.75 m solution, and dilute it to 2.00 l.

measure 8.75 ml of the 1.75 m solution, and dilute it to 2.00 l.

measure 8.75 ml of the 0.100 m solution, and dilute it to 2.00 l.

Measure 114 mL of the 1.75 M solution, and dilute it to 2.00 L.

Explanation:

The number of moles in the solution will remain same on dilution and thus according to Molarity Equation:

= molarity of first solution

= Volume of first solution

= molarity of second solution

= Volume of second solution

Thus 114 ml of 1.75 M solution is taken and the volume is diluted to 2.0 L to make 0.100 M solution.

- aluminum and copper chloride.

- the chloride ion to separate the aluminum from the oxygen so that the aluminum can react with the copper ions (and the water molecules).