Given that the molar mass of h2o is 18.02 g/mol, how many liters of propane are required at stp to produce 75 g of h2o from this reaction?

We need a balanced equation:

C₃H₈ + 5O₂ ---> 3CO₂ + 4H₂O

let's convert the grams of water to moles using the molar mass. then mole-mole ratio to convert to moles of propane. finally, convert moles to Liters using the STP molar volume (1 mol= 22.4 L)

Hi; /c