Hey again matt! i have another question if you can me! how many grams of magnesium oxide can be produced when 97.2 g mg react with 88.5 g o2? the unbalanced equation is: mg + o2 → mgo i already balanced the equation to 2mg + o2 → 2mgo

2Mg + O₂ = 2MgO

n(Mg)=m(Mg)/M(Mg)
n(Mg)=97.2g/24.3g/mol=4 mol

n(O₂)=m(O₂)/M(O₂)
n(O₂)=88.5 g/32.0 g/mol=2.77 mol

Mg:O₂  2:1   4:2
4:2.77
the oxygen is in excess
the calculation for the magnesium

n(MgO)=n(Mg)

m(MgO)=n(Mg)*M(MgO)

m(MgO)=4 mol * 40.3 g/mol = 161.2 g

161.2 grams of magnesium oxide can be produced

That result from subduction of oceanic plates beneath lighter continental plates. most of the earth's volcanoes are located around the pacific ring of fire because that the location of most of the earth's subduction zones.

The answer is probably c. xylem