If 27.3 ml of 0.293 m hbr solution completely neutralizes 42.6 ml of nh3, what is the concentration of the nh3 solution? nh3 + hbr yields nh4br 0.188 m 0.387 m 0.586 m 2.18 m

According to reaction equation: NH3+HBr=NH4Br, 1 mole of NH3 is required to react with 1 mole of HBr.  HBr solution contains 0.0273L * 0.293M = 0.008 moles of HBr.  Therefore 0.008 mole of NH3 is reacted. So the concentration of NH3 is 0.008 mole/0.0426 L = 0.188M.  The answer is 0.188M.

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na

Answerδh > 0explanationc₆h₆  (s)  → c₆h₆ (l)if you are changing it from a solid to a liquid, you are pretty much melting the solid. this requires heat energy. therefore, the reaction is endothermic (takes in energy); the system enthalpy increases as the reaction proceeds: δh > 0.