What is the empirical formula of a compound that contains 50.0% carbon, 6.7% hydrogen, and 43.3% oxygen by mass?

Assume 100 g of unknown compound.

 50.0⋅g 12.011⋅g⋅mol−1 = 4.163 mol⋅C.

 6.7⋅g 1.00794⋅g⋅mol−1 = 6.65 mol⋅H.

 43.3⋅g 15.999⋅g⋅mol−1 = 2.71 mol⋅O.

divide thru by the lowest molar quantity, that of oxygen to get a formula of C1.54H2.45O1,  double to give a whole number EMPIRICAL formula of C3H5O2