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Chemistry, 06.10.2019 17:20 janiadavis35

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a force of 2,500 pounds drags a truck 30 feet in 1/2 minute.

how much work is accomplished?

how much power was required?

work = 75,000 ft-lbs, power = 32, 5000 ft-lbs/sec
work = 7,500 ft-lbs, power = 250 ft-lbs/sec
work= 75,000 ft-lbs, power = 2,500 ft-lbs/sec

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