Calculate the mole fraction of the total ions in an aqueous solution prepared by dissolving 0.400 moles of mgbr2 in 850.0 g of water

Answer : The mole fraction of the total ions in an aqueous solution is 0.0248

Explanation :

First we have to calculate the moles of water.

Now we have to calculate the moles of magnesium ion and bromide ion.

As we are given that 0.4 moles of that means, there are 0.4 moles of magnesium ion and 0.8 moles of bromide ions.

Total mole of ions in an aqueous solution = 0.4 + 0.8 = 1.2 mole

Now we have to calculate the mole fraction of the total ions in an aqueous solution.

Therefore, the mole fraction of the total ions in an aqueous solution is 0.0248

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.