Why is the hybridization of [cr(h2o)6]3+ d2sp3 and not sp3d2?

A inner d orbital complex must be proposed.

Explanation:

Hello,

It is seen that in this complex the total charge is +3 as long as the is neutral. Therefore, its electron configuration is:

It means that it has three electrons on 3d sublevel zero on 4s and zero on 4p. Thus, the hybridization comes up from the  fact we've got to complete the hollow spaces (six as there are six waters) into a whole "inner d orbital complex" that is:

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a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.