How many milliliters of 0.45 m hcl will neutralize 25.0 ml of 1.00 m koh?

55.55 mL of HCl 0.45 m are needed to neutralize 25 mL of 1 m KOH

Explanation:

The equation that describes the reaction is:

We can see that one mole of HCl is needed to consume one mole of KOH

Looking at the units:

So, kepping in mind the previous statements, we proceed to calculate the total moles of KOH in the solution:

Now we know that we need 0.025 MOL of HCl to neutralize the solution; So:

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