You might have a flashlight that runs (2) d-cells of 1.5 volts each in series. the bulb is rated for 0.7 amps. what’s its resistance?

The value of resistance is 4.28 Ω.

Explanation:

Voltage of single d-cells = 1.5 V

Two d-cells are in series with in a flashlight.

(series arrangement)

So, Total voltage in the flash light:

V = 1.5 V + 1.5 V = 3.0 V

Electrical Current rating of the bulb I= 0.7 A

let the resistance be R

(Ohms law}

The value of resistance is 4.28 Ω.