What is the mass in grams of 9.06 x 10^24 molecules of methanol (ch3oh)?

Explanation:

As we know that according to Avogadro, 1 mole of an atom contains atoms.

So, number of atoms given in the methanol are . Hence, calculate the number of moles present as follows.

   No. of moles =

                         = 15.04 mol    

As molar mass of methanol is 32.04 g/mol. Hence, the mass of given methanol is as follows.

          No. of moles =

               15.04 mol =

             mass = 481.28 g

Thus, we can conclude that mass of molecules of methanol () is 481.28 g.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3