Chemistry, 15.11.2019 17:31 KitKat22Rose9

Acertain radioisotope has a half-life of 8.0 hours; how much of a 192 g sample of this radioisotope would decay after a full day?

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Answer from: ineedhelpwhomework

167.9895 grams sample of this radioisotope would decay after a full day.

Explanation:

$N=N_o\times e^{-\lambda t}$

$\lambda =\frac{0.693}{t_{1/2}}$

N_o = initial amount of radioisotope

N = Amount of radioisotope left after time t.

$\lambda$ = Decay Constant

$t_{1/2}$ = Half life of the radioisotope

We have:

N_o=192 g

$t_{1/2}=8.0 hours$

t = 1 day = 24 hour

$\lambda =\frac{0.693}{8.0 hour}=0.086625 hour^{-1}$

$N=192 g\times e^{-0.086625 hour^{-1}\times 24 hours}$

N = 24.0105 g

24.0105 grams of radioisotope will remain after 1 whole day.

Amount of radioisotope decayed = N_o-N=192 g- 24.0105 g=167.9895 g

167.9895 grams sample of this radioisotope would decay after a full day.

Answer from: Quest

remember that hf is only the energy of one photon. not two. not three. one. 1) 5.12 * 10^3 photons find the energy of one photon, then determine how many photons are needed to reach the sensitivity. e = hf = (6.626 * 10^-34 js)(5.95 * 10^19 hz) = 3.94247 * 10^-14 j per photon (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons round to three sig figs. 2) 5.77 * 10^-17 j energy of pulse = energy per photon * number of photons = hfn = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250) = 5.774559 * 10^-17 j round to three sig figs. 3) 4.07 * 10^8 kj/mol 10^12 pm = 1 m c = fλ f = c/λ e = hf = hc/λ = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol) = 40702571.4 kj/mol round to three sig figs. 4) 9.94 * 10^-1 m e = hc/λ λ = hc / e = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j) = 0.9939 m round to three sig figs. 5) 9.06 * 10^3 photons energy of pulse = energy per photon * number of photons number of photons = energy of pulse / energy per photon = energy of pulse / (hf) = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)] = 9055.23695 photons round to three sig figs. 6) 2.78 * 10^-15 j this is problem 1, except in reverse. sensitivity = minumum number of photons * energy per photon = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz) = 2.78070758 × 10^-15 j round to three sig figs.

Answer from: Quest

Mg-26 and mg-24 are pair of isotopes. isotopes are defined as atoms of the same element having same atomic number but different mass number. i hope that was .

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Acertain radioisotope has a half-life of 8.0 hours; how much of a 192 g sample of this radioisotope...