If the emf produced in a wire is 0.88 volts and the wire moves perpendicular to a magnetic field of strength 0.075 newtons/amp·meter at a speed of 4.20 meters/second, what is the length of the wire in the magnetic field?

a.0.27 meters
b.2.8 meters
c.0.020 meters
d.3.7 meters

B = 0.075 N/amp*m

V = 4.20 m/s

EMF = 0.88 Volts

L = ?

Formula = EMF = L x B x V

Since we have EMF and we’re looking for L, the formula will now be: 

L = EMF x B x V

Solution:

= 0.88 x 0.075 x 4.2

= 2.8

The length of the wire in the magnetic field is 2.8m

The answer is letter B.

h

d.) circle motion requires a force to give it a centripetal acceleration.